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For a secondary clarifier that is 75 ft in diameter with a combined flow of 4.0 mgd and a MLSS concentration of 2450 mg/L, what is the solids loading rate?

14 lb/d/ft2

17 lb/d/ft2

12 lb/d/ft2

19 lb/d/ft2

To determine the solids loading rate for a secondary clarifier, the formula used is:

\[

\text{Solids Loading Rate} = \frac{\text{Flow Rate} \times \text{MLSS Concentration}}{\text{Surface Area of the Clarifier}}

\]

First, we need to calculate the surface area of the clarifier. The area of a circular tank can be calculated using the formula:

\[

\text{Area} = \pi \times \left(\frac{\text{Diameter}}{2}\right)^2

\]

With a diameter of 75 feet:

\[

\text{Area} = \pi \times \left(\frac{75}{2}\right)^2 \approx 4417.86 \text{ ft}^2

\]

Next, we convert the flow rate from mgd (million gallons per day) to gallons per minute (gpm) for easier calculations. Since 1 mgd equals 1,000,000 gallons per day and there are 1,440 minutes in a day:

\[

4.0 \text{ mgd} = 4,000,000 \text{ gallons per day} \div 1,440

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